Maths Blog 1

Hello everyone, we hope you are all safe and well and are enjoying some of the activities we have been putting on the Virtual School! We have created a new maths blog where you will be able to access the White Rose maths and take part in some additional maths challenges.


We will upload a new maths blog each Monday, with new challenges and to let you know which White Rose maths lessons we would like you to complete that week. We will upload the answers to the challenges on Friday!


If you know of any good maths challenges, we would love you to send them in to put on our blog to see if everyone else can complete the challenge!


White Rose Lessons:

- Year 5: Summer Term, Week 2, Lessons 1-5

- Year 6: Summer Term, Week 2, Lessons 1-5


Challenges for Blog 1:


Challenge 1:

This one is just algebra. Let’s assign some letters:

R = Red, B = Blue, Y = Yellow

R + R + R = 60 Add R’s together: 3R = 60 Divide both sides by 3: R = 20

R + B + B = 30 Substitute R: 20 + B + B = 30

Add B’s together = 20 + 2B = 30 Subtract 20 from both sides: 2B = 10 Divide both sides by 2: B = 5

B – 2Y = 3 Substitute B: 5 – 2Y = 3 Subtract 5 from both sides -2Y = -2 Divide both sides by -2: Y = 1

R + Y + B = ? Substitute values: 20 + 1 + 5 = ?

Answer is 26. Did you get it? Did you notice there are two stems for the yellow flower in the third equation?



Challenge 2 - make sure you look at the pictures VERY closely:

This one starts the same as the previous puzzle. Let’s assign some letters:

R = Red, B = Blue, Y = Yellow

R + R + R = 60 Add R’s together: 3R = 60 Divide both sides by 3: R = 20

R + B + B = 30 Substitute R: 20 + B + B = 30 Add B’s together = 20 + 2B = 30 Subtract 20 from both sides: 2B = 10 Divide both sides by 2: B = 5

B – 2Y = 3 Substitute B: 5 – 2Y = 3 Subtract 5 from both sides -2Y = -2 Divide both sides by -2: Y = 1

Y + R x (4/5)B = ? Substitute values: 1 + 20 x (4/5)5 = ? Brackets first: 1 + 20 x 4 = ? Then Multiply: 1 + 80 = ? Addition: 81 = ?

Answer is 81. Did you get it? Did you notice that the final blue flower only had four of the five petals the others had and so is only worth 4/5 or 80% of the full value for blue?


Challenge 3:



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